【第六章】实验5 编写、调试具有多个段的程序

我的答案：运用段寄存器，对单字节进行操作

assume cs:code,ds:a,ss:b,es:c

a segment
	db 1,2,3,4,5,6,7,8
a ends

b segment
	db 1,2,3,4,5,6,7,8
b ends

c segment
	db 0,0,0,0,0,0,0,0
c ends

code segment
start:	mov ax,a
	mov ds,ax
	
	mov ax,b
	mov ss,ax
	mov sp,0000

	mov ax,c
	mov es,ax

	mov cx,8
	mov bx,0
s:	pop ax
	dec sp ;pop一次sp+2，我们想操作单字节，需要将pop-1
	mov es:[bx],al  ;低位存储的是低地址的数据

	mov ax,ds:[bx]
	add es:[bx],al
	inc bx
	loop s

	mov ax,4c00h
	int 21h
code ends
end start

官方答案：

assume cs:code
a segment
	db 1,2,3,4,5,6,7,8
a ends
b segment
	db 1,2,3,4,5,6,7,8
b ends
c segment
	db 0,0,0,0,0,0,0,0
c ends

code segment 

start:
	mov ax,a
	mov ds,ax
	
	mov cx,8
	mov bx,0
s:
	;每次虽然加上一个字的数据，但是更新后并不影响
	mov ax,ds:[bx]
	add bx,20h
	mov ds:[bx],ax
	sub bx,10h
	mov ax,ds:[bx]
	add bx,10h
	add ax,ds:[bx]
	mov ds:[bx],ax
	sub bx,20h
	
	inc bx
	loop s
code ends

end start

更简洁的写法：

assume cs:code
a segment
	db 1,2,3,4,5,6,7,8
a ends
b segment
	db 1,2,3,4,5,6,7,8
b ends
c segment
	db 0,0,0,0,0,0,0,0
c ends

code segment 

start:
	mov ax,a
	mov ds,ax
	
	mov cx,8
	mov bx,0
s:
	
	mov ax,ds:[bx]
	mov ds:20h[bx],ax
	mov ax,ds:10h[bx]
	add ax,ds:20h[bx]
	mov ds:20h[bx],ax
	
	inc bx
	loop s
code ends

end start
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原文链接：<https://blog.csdn.net/happy_Du/article/details/107395870>