【实例】 C语言实现扫雷

头文件game.h

#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>
#include <time.h>
#include <stdlib.h>

#define ROW 9
#define COL 9
#define ROWS ROW+2
#define COLS COL+2

#define EASY_COUNT 10

void InitBoard(char board[ROWS][COLS], int rows, int cols, char set);
void DisplayBoard(char board[ROWS][COLS], int row, int col);
void SetMine(char board[ROWS][COLS], int row, int col);
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);

源文件test.c

#include "game.h"

void menu() {
	printf("*********************\\n");
	printf("****0.exit 1.play****\\n");
	printf("*********************\\n");
}

void game() {
	//雷的存储信息
	//1.布置好的雷的信息 11*11
	static char mine[ROWS][COLS] = { 0 };
	//2.排查出的雷的信息 9*9
	static char show[ROW][COL] = { 0 };
	//初始化游戏棋盘
	InitBoard(mine, ROWS, COLS,'0');
	InitBoard(show, ROWS, COLS, '*');
	//打印棋盘
	//因为不要打印最外层的两行，所以传进的参数为9*9
	DisplayBoard(show, ROW, COL);
	//设置雷
	SetMine(mine, ROW, COL);
	//DisplayBoard(mine, ROW, COL);
	//扫雷游戏算法实现
	FindMine(mine, show, ROW, COL);
}

void test() {
	int input = 0;
	do {
		menu();
		srand((unsigned int)time(NULL));
		scanf("%d", &input);
		switch (input) {
			case 0:
				printf("游戏结束\\n");
				break;
			case 1:
				printf("游戏开始\\n");
				game();
				break;
			default:
				printf("输入有误，请重新输入\\n");
				break;
		}
	} while (input);
}

int main() {
	test();
	return 0;
}

源文件 game.c

#include "game.h"

void InitBoard(char board[ROWS][COLS], int rows, int cols, char set) {
	int i = 0;
	int j = 0;
	for (; i < rows; i++) {
		for (j = 0; j < cols; j++) {
			board[i][j] = set;
		}
	}
}

void DisplayBoard(char board[ROWS][COLS], int row, int col) {
	int i = 0;
	int j = 0;
	for (int k = 0; k <= col; k++) {
		printf("%d ", k);
	}
	printf("\\n");
	for (i = 1; i <= row; i++) {
		printf("%d ", i);
		for (j = 1; j <= col; j++) {
			printf("%c ", board[i][j]);
		}
		printf("\\n");
	}
	printf("\\n");
}

void SetMine(char board[ROWS][COLS], int row, int col) {
	int count = EASY_COUNT;
	while (count) {
		int x = rand() % row+1;//x范围为1-9
		int y = rand() % col+1;//y范围为1-9
		if (board[x][y] == '0')
		{
			board[x][y] = '1';
			count--;
		}
	}
}

//在ASCII表中:字符3是字符0+3，所以'3'='0'+3。
//'3'-'0' = 3;
//'1'-'0' = 1;
int get_mine_count(char mine[ROWS][COLS], int x, int y) {
	return mine[x - 1][y - 1] + mine[x - 1][y] +
		mine[x - 1][y + 1] + mine[x][y - 1] +
		mine[x][y+1] + mine[x+1][y - 1] +
		mine[x + 1][y] + mine[x + 1][y + 1] - 8 * '0';
}

void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col) {
	int x = 0;
	int y = 0;
	int win = 0;
	while (win < row*col-EASY_COUNT) {
		printf("请输入要排查的坐标：\\n");
		scanf("%d%d", &x, &y);
		if (x >= 1 && x <= row && y >= 1 && y <= col) {
			//坐标合法
			//1.踩雷
			if (mine[x][y] == '1') {
				printf("很遗憾，您被炸死了。游戏结束\\n");
				DisplayBoard(mine, row, col);
				break;
			}
			//2.非雷
			else {
				//计算x、y坐标周围有几个雷
				int count = get_mine_count(mine, x, y);
				show[x][y] = count + '0';
				DisplayBoard(show, row, col);
				win++;
			}
		}
		else {
			printf("输入坐标有误，请重新输入\\n");
		}
	}
	if (win == row * col - EASY_COUNT) {
		printf("恭喜你，排雷成功！\\n");
		DisplayBoard(show, row, col);
	}
}